5(z-5)+(4z-2)=

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Solution for 5(z-5)+(4z-2)= equation:


Simplifying
5(z + -5) + (4z + -2) = 0

Reorder the terms:
5(-5 + z) + (4z + -2) = 0
(-5 * 5 + z * 5) + (4z + -2) = 0
(-25 + 5z) + (4z + -2) = 0

Reorder the terms:
-25 + 5z + (-2 + 4z) = 0

Remove parenthesis around (-2 + 4z)
-25 + 5z + -2 + 4z = 0

Reorder the terms:
-25 + -2 + 5z + 4z = 0

Combine like terms: -25 + -2 = -27
-27 + 5z + 4z = 0

Combine like terms: 5z + 4z = 9z
-27 + 9z = 0

Solving
-27 + 9z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '27' to each side of the equation.
-27 + 27 + 9z = 0 + 27

Combine like terms: -27 + 27 = 0
0 + 9z = 0 + 27
9z = 0 + 27

Combine like terms: 0 + 27 = 27
9z = 27

Divide each side by '9'.
z = 3

Simplifying
z = 3

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