5(z-5)=2(2z+1)

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Solution for 5(z-5)=2(2z+1) equation: 



5(z-5)=2(2z+1)

We move all terms to the left:

5(z-5)-(2(2z+1))=0

We multiply parentheses

5z-(2(2z+1))-25=0



We calculate terms in parentheses: -(2(2z+1)), so:

2(2z+1)

We multiply parentheses

4z+2

Back to the equation:

-(4z+2)



We get rid of parentheses

5z-4z-2-25=0

We add all the numbers together, and all the variables

z-27=0

We move all terms containing z to the left, all other terms to the right

z=27

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