5*(2r-1)-3*(2r+1)=4-3*(r-3)

Solution for 5*(2r-1)-3*(2r+1)=4-3*(r-3) equation:

5(2r-1)-3(2r+1)=4-3(r-3)

We move all terms to the left:

5(2r-1)-3(2r+1)-(4-3(r-3))=0

We multiply parentheses

10r-6r-(4-3(r-3))-5-3=0


We calculate terms in parentheses: -(4-3(r-3)), so:

4-3(r-3)

determiningTheFunctionDomain
-3(r-3)+4

We multiply parentheses

-3r+9+4

We add all the numbers together, and all the variables

-3r+13

Back to the equation:

-(-3r+13)


We add all the numbers together, and all the variables

4r-(-3r+13)-8=0

We get rid of parentheses

4r+3r-13-8=0

We add all the numbers together, and all the variables

7r-21=0

We move all terms containing r to the left, all other terms to the right

7r=21

r=21/7

r=3