5*(2x-4)=10-2*(x-3)

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Solution for 5*(2x-4)=10-2*(x-3) equation: 



5(2x-4)=10-2(x-3)

We move all terms to the left:

5(2x-4)-(10-2(x-3))=0

We multiply parentheses

10x-(10-2(x-3))-20=0



We calculate terms in parentheses: -(10-2(x-3)), so:

10-2(x-3)

determiningTheFunctionDomain
-2(x-3)+10

We multiply parentheses

-2x+6+10

We add all the numbers together, and all the variables

-2x+16

Back to the equation:

-(-2x+16)



We get rid of parentheses

10x+2x-16-20=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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