5*(x+2)*(x-2)=0

Solution for 5*(x+2)*(x-2)=0 equation:

Simplifying
5(x + 2)(x + -2) = 0

Reorder the terms:
5(2 + x)(x + -2) = 0

Reorder the terms:
5(2 + x)(-2 + x) = 0

Multiply (2 + x) * (-2 + x)
5(2(-2 + x) + x(-2 + x)) = 0
5((-2 * 2 + x * 2) + x(-2 + x)) = 0
5((-4 + 2x) + x(-2 + x)) = 0
5(-4 + 2x + (-2 * x + x * x)) = 0
5(-4 + 2x + (-2x + x2)) = 0

Combine like terms: 2x + -2x = 0
5(-4 + 0 + x2) = 0
5(-4 + x2) = 0
(-4 * 5 + x2 * 5) = 0
(-20 + 5x2) = 0

Solving
-20 + 5x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 5x2 = 0 + 20

Combine like terms: -20 + 20 = 0
0 + 5x2 = 0 + 20
5x2 = 0 + 20

Combine like terms: 0 + 20 = 20
5x2 = 20

Divide each side by '5'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}