5*(x+2)-2*(x-3)=4+4*(x+3)

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Solution for 5*(x+2)-2*(x-3)=4+4*(x+3) equation: 



5(x+2)-2(x-3)=4+4(x+3)

We move all terms to the left:

5(x+2)-2(x-3)-(4+4(x+3))=0

We multiply parentheses

5x-2x-(4+4(x+3))+10+6=0



We calculate terms in parentheses: -(4+4(x+3)), so:

4+4(x+3)

determiningTheFunctionDomain
4(x+3)+4

We multiply parentheses

4x+12+4

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

3x-(4x+16)+16=0

We get rid of parentheses

3x-4x-16+16=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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