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5*(x+3)=95-5*(12+x)
We move all terms to the left:
5*(x+3)-(95-5*(12+x))=0
We add all the numbers together, and all the variables
5*(x+3)-(95-5*(x+12))=0
We multiply parentheses
5x-(95-5*(x+12))+15=0
We calculate terms in parentheses: -(95-5*(x+12)), so:We get rid of parentheses
95-5*(x+12)
determiningTheFunctionDomain -5*(x+12)+95
We multiply parentheses
-5x-60+95
We add all the numbers together, and all the variables
-5x+35
Back to the equation:
-(-5x+35)
5x+5x-35+15=0
We add all the numbers together, and all the variables
10x-20=0
We move all terms containing x to the left, all other terms to the right
10x=20
x=20/10
x=2
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