5*(x+4)=7-3*(2-5*x)

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Solution for 5*(x+4)=7-3*(2-5*x) equation:



5(x+4)=7-3(2-5x)
We move all terms to the left:
5(x+4)-(7-3(2-5x))=0
We add all the numbers together, and all the variables
5(x+4)-(7-3(-5x+2))=0
We multiply parentheses
5x-(7-3(-5x+2))+20=0
We calculate terms in parentheses: -(7-3(-5x+2)), so:
7-3(-5x+2)
determiningTheFunctionDomain -3(-5x+2)+7
We multiply parentheses
15x-6+7
We add all the numbers together, and all the variables
15x+1
Back to the equation:
-(15x+1)
We get rid of parentheses
5x-15x-1+20=0
We add all the numbers together, and all the variables
-10x+19=0
We move all terms containing x to the left, all other terms to the right
-10x=-19
x=-19/-10
x=1+9/10

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