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5(x-4)=3(x+2)
We move all terms to the left:
5(x-4)-(3(x+2))=0
We multiply parentheses
5x-(3(x+2))-20=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
5x-3x-6-20=0
We add all the numbers together, and all the variables
2x-26=0
We move all terms containing x to the left, all other terms to the right
2x=26
x=26/2
x=13
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