5*(z+2)=6*(z-1)

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Solution for 5*(z+2)=6*(z-1) equation: 


Simplifying
5(z + 2) = 6(z + -1)

Reorder the terms:
5(2 + z) = 6(z + -1)
(2 * 5 + z * 5) = 6(z + -1)
(10 + 5z) = 6(z + -1)

Reorder the terms:
10 + 5z = 6(-1 + z)
10 + 5z = (-1 * 6 + z * 6)
10 + 5z = (-6 + 6z)

Solving
10 + 5z = -6 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
10 + 5z + -6z = -6 + 6z + -6z

Combine like terms: 5z + -6z = -1z
10 + -1z = -6 + 6z + -6z

Combine like terms: 6z + -6z = 0
10 + -1z = -6 + 0
10 + -1z = -6

Add '-10' to each side of the equation.
10 + -10 + -1z = -6 + -10

Combine like terms: 10 + -10 = 0
0 + -1z = -6 + -10
-1z = -6 + -10

Combine like terms: -6 + -10 = -16
-1z = -16

Divide each side by '-1'.
z = 16

Simplifying
z = 16

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