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5+(1/4)x+2=1
We move all terms to the left:
5+(1/4)x+2-(1)=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/4)x+5+2-1=0
We add all the numbers together, and all the variables
(+1/4)x+6=0
We multiply parentheses
x^2+6=0
a = 1; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·1·6
Δ = -24
Delta is less than zero, so there is no solution for the equation
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