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5+(2-3x)-(1-x)=2x-2(x-3)
We move all terms to the left:
5+(2-3x)-(1-x)-(2x-2(x-3))=0
We add all the numbers together, and all the variables
(-3x+2)-(-1x+1)-(2x-2(x-3))+5=0
We get rid of parentheses
-3x+1x-(2x-2(x-3))+2-1+5=0
We calculate terms in parentheses: -(2x-2(x-3)), so:We add all the numbers together, and all the variables
2x-2(x-3)
We multiply parentheses
2x-2x+6
We add all the numbers together, and all the variables
6
Back to the equation:
-(6)
-2x=0
x=0/-2
x=0
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