5+(2r-3)=r-(3r+10)

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Solution for 5+(2r-3)=r-(3r+10) equation: 



5+(2r-3)=r-(3r+10)

We move all terms to the left:

5+(2r-3)-(r-(3r+10))=0

We get rid of parentheses

2r-(r-(3r+10))-3+5=0



We calculate terms in parentheses: -(r-(3r+10)), so:

r-(3r+10)

We get rid of parentheses

r-3r-10

We add all the numbers together, and all the variables

-2r-10

Back to the equation:

-(-2r-10)



We add all the numbers together, and all the variables

2r-(-2r-10)+2=0

We get rid of parentheses

2r+2r+10+2=0

We add all the numbers together, and all the variables

4r+12=0

We move all terms containing r to the left, all other terms to the right

4r=-12

r=-12/4

r=-3

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