5+(2y+1)=3(y-3)

Solution for 5+(2y+1)=3(y-3) equation:

5+(2y+1)=3(y-3)

We move all terms to the left:

5+(2y+1)-(3(y-3))=0

We get rid of parentheses

2y-(3(y-3))+1+5=0


We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)


We add all the numbers together, and all the variables

2y-(3y-9)+6=0

We get rid of parentheses

2y-3y+9+6=0

We add all the numbers together, and all the variables

-1y+15=0

We move all terms containing y to the left, all other terms to the right

-y=-15

y=-15/-1

y=+15