5+(8x-2)=(3x+1)4+1

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Solution for 5+(8x-2)=(3x+1)4+1 equation: 



5+(8x-2)=(3x+1)4+1

We move all terms to the left:

5+(8x-2)-((3x+1)4+1)=0

We get rid of parentheses

8x-((3x+1)4+1)-2+5=0



We calculate terms in parentheses: -((3x+1)4+1), so:

(3x+1)4+1

We multiply parentheses

12x+4+1

We add all the numbers together, and all the variables

12x+5

Back to the equation:

-(12x+5)



We add all the numbers together, and all the variables

8x-(12x+5)+3=0

We get rid of parentheses

8x-12x-5+3=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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