5+(x+2)+(3x-4)=15

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Solution for 5+(x+2)+(3x-4)=15 equation: 



5+(x+2)+(3x-4)=15

We move all terms to the left:

5+(x+2)+(3x-4)-(15)=0

We add all the numbers together, and all the variables

(x+2)+(3x-4)-10=0

We get rid of parentheses

x+3x+2-4-10=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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