5+(z+4)=50

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Solution for 5+(z+4)=50 equation: 



5+(z+4)=50

We move all terms to the left:

5+(z+4)-(50)=0

We add all the numbers together, and all the variables

(z+4)-45=0

We get rid of parentheses

z+4-45=0

We add all the numbers together, and all the variables

z-41=0

We move all terms containing z to the left, all other terms to the right

z=41

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