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5+-4x+12x2=0

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Solution for 5+-4x+12x2=0 equation:



5+-4x+12x^2=0
We add all the numbers together, and all the variables
12x^2-4x=0
a = 12; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·12·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{16}=4
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*12}=\frac{0}{24} =0
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*12}=\frac{8}{24} =1/3

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