5+1/2(2f+10)=1/3(6f-4)

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Solution for 5+1/2(2f+10)=1/3(6f-4) equation:


f in (-oo:+oo)

(1/2)*(2*f+10)+5 = (1/3)*(6*f-4) // - (1/3)*(6*f-4)

(1/2)*(2*f+10)-((1/3)*(6*f-4))+5 = 0

(1/2)*(2*f+10)+(-1/3)*(6*f-4)+5 = 0

1/2*(2*f+10)-1/3*(6*f-4)+5 = 0

1/2*(2*f+10)-1/3*(6*f-4)+5 = 0

5-f+19/3 = 0

34/3-f = 0

34/3-f = 0

34/3-f = 0 // - 34/3

-f = -34/3 // * -1

f = 34/3

f = 34/3

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