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5+1/2x=3/5x-3
We move all terms to the left:
5+1/2x-(3/5x-3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x-3)!=0We get rid of parentheses
x∈R
1/2x-3/5x+3+5=0
We calculate fractions
5x/10x^2+(-6x)/10x^2+3+5=0
We add all the numbers together, and all the variables
5x/10x^2+(-6x)/10x^2+8=0
We multiply all the terms by the denominator
5x+(-6x)+8*10x^2=0
Wy multiply elements
80x^2+5x+(-6x)=0
We get rid of parentheses
80x^2+5x-6x=0
We add all the numbers together, and all the variables
80x^2-1x=0
a = 80; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·80·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*80}=\frac{0}{160} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*80}=\frac{2}{160} =1/80 $
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