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5+1/3x=2x
We move all terms to the left:
5+1/3x-(2x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-2x+1/3x+5=0
We multiply all the terms by the denominator
-2x*3x+5*3x+1=0
Wy multiply elements
-6x^2+15x+1=0
a = -6; b = 15; c = +1;
Δ = b2-4ac
Δ = 152-4·(-6)·1
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{249}}{2*-6}=\frac{-15-\sqrt{249}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{249}}{2*-6}=\frac{-15+\sqrt{249}}{-12} $
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