5+2(2y-1)=-2(3y-9)+y

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Solution for 5+2(2y-1)=-2(3y-9)+y equation: 



5+2(2y-1)=-2(3y-9)+y

We move all terms to the left:

5+2(2y-1)-(-2(3y-9)+y)=0

We multiply parentheses

4y-(-2(3y-9)+y)-2+5=0



We calculate terms in parentheses: -(-2(3y-9)+y), so:

-2(3y-9)+y

We add all the numbers together, and all the variables

y-2(3y-9)

We multiply parentheses

y-6y+18

We add all the numbers together, and all the variables

-5y+18

Back to the equation:

-(-5y+18)



We add all the numbers together, and all the variables

4y-(-5y+18)+3=0

We get rid of parentheses

4y+5y-18+3=0

We add all the numbers together, and all the variables

9y-15=0

We move all terms containing y to the left, all other terms to the right

9y=15

y=15/9

y=1+2/3

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