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5+2(3x+1)+11=6+3(3x+4)+2x
We move all terms to the left:
5+2(3x+1)+11-(6+3(3x+4)+2x)=0
We add all the numbers together, and all the variables
2(3x+1)-(6+3(3x+4)+2x)+16=0
We multiply parentheses
6x-(6+3(3x+4)+2x)+2+16=0
We calculate terms in parentheses: -(6+3(3x+4)+2x), so:We add all the numbers together, and all the variables
6+3(3x+4)+2x
determiningTheFunctionDomain 3(3x+4)+2x+6
We add all the numbers together, and all the variables
2x+3(3x+4)+6
We multiply parentheses
2x+9x+12+6
We add all the numbers together, and all the variables
11x+18
Back to the equation:
-(11x+18)
6x-(11x+18)+18=0
We get rid of parentheses
6x-11x-18+18=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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