5+2(3x-4)=6+3(4x-7)

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Solution for 5+2(3x-4)=6+3(4x-7) equation: 



5+2(3x-4)=6+3(4x-7)

We move all terms to the left:

5+2(3x-4)-(6+3(4x-7))=0

We multiply parentheses

6x-(6+3(4x-7))-8+5=0



We calculate terms in parentheses: -(6+3(4x-7)), so:

6+3(4x-7)

determiningTheFunctionDomain
3(4x-7)+6

We multiply parentheses

12x-21+6

We add all the numbers together, and all the variables

12x-15

Back to the equation:

-(12x-15)



We add all the numbers together, and all the variables

6x-(12x-15)-3=0

We get rid of parentheses

6x-12x+15-3=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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