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5+2(3x-6)=9-3(2x+1)
We move all terms to the left:
5+2(3x-6)-(9-3(2x+1))=0
We multiply parentheses
6x-(9-3(2x+1))-12+5=0
We calculate terms in parentheses: -(9-3(2x+1)), so:We add all the numbers together, and all the variables
9-3(2x+1)
determiningTheFunctionDomain -3(2x+1)+9
We multiply parentheses
-6x-3+9
We add all the numbers together, and all the variables
-6x+6
Back to the equation:
-(-6x+6)
6x-(-6x+6)-7=0
We get rid of parentheses
6x+6x-6-7=0
We add all the numbers together, and all the variables
12x-13=0
We move all terms containing x to the left, all other terms to the right
12x=13
x=13/12
x=1+1/12
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