5+2(3y-4)=27

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Solution for 5+2(3y-4)=27 equation: 



5+2(3y-4)=27

We move all terms to the left:

5+2(3y-4)-(27)=0

We add all the numbers together, and all the variables

2(3y-4)-22=0

We multiply parentheses

6y-8-22=0

We add all the numbers together, and all the variables

6y-30=0

We move all terms containing y to the left, all other terms to the right

6y=30

y=30/6

y=5

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