5+2(4c-8)=5c+3(c-4)+1

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Solution for 5+2(4c-8)=5c+3(c-4)+1 equation: 



5+2(4c-8)=5c+3(c-4)+1

We move all terms to the left:

5+2(4c-8)-(5c+3(c-4)+1)=0

We multiply parentheses

8c-(5c+3(c-4)+1)-16+5=0



We calculate terms in parentheses: -(5c+3(c-4)+1), so:

5c+3(c-4)+1

We multiply parentheses

5c+3c-12+1

We add all the numbers together, and all the variables

8c-11

Back to the equation:

-(8c-11)



We add all the numbers together, and all the variables

8c-(8c-11)-11=0

We get rid of parentheses

8c-8c+11-11=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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