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5+2(4x-4)=5-4(2x+1)
We move all terms to the left:
5+2(4x-4)-(5-4(2x+1))=0
We multiply parentheses
8x-(5-4(2x+1))-8+5=0
We calculate terms in parentheses: -(5-4(2x+1)), so:We add all the numbers together, and all the variables
5-4(2x+1)
determiningTheFunctionDomain -4(2x+1)+5
We multiply parentheses
-8x-4+5
We add all the numbers together, and all the variables
-8x+1
Back to the equation:
-(-8x+1)
8x-(-8x+1)-3=0
We get rid of parentheses
8x+8x-1-3=0
We add all the numbers together, and all the variables
16x-4=0
We move all terms containing x to the left, all other terms to the right
16x=4
x=4/16
x=1/4
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