5+2(4x-4)=8-3(2x+1)

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Solution for 5+2(4x-4)=8-3(2x+1) equation: 



5+2(4x-4)=8-3(2x+1)

We move all terms to the left:

5+2(4x-4)-(8-3(2x+1))=0

We multiply parentheses

8x-(8-3(2x+1))-8+5=0



We calculate terms in parentheses: -(8-3(2x+1)), so:

8-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+8

We multiply parentheses

-6x-3+8

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)



We add all the numbers together, and all the variables

8x-(-6x+5)-3=0

We get rid of parentheses

8x+6x-5-3=0

We add all the numbers together, and all the variables

14x-8=0

We move all terms containing x to the left, all other terms to the right

14x=8

x=8/14

x=4/7

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