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5+2(5x-6)=6-4(2x+1)
We move all terms to the left:
5+2(5x-6)-(6-4(2x+1))=0
We multiply parentheses
10x-(6-4(2x+1))-12+5=0
We calculate terms in parentheses: -(6-4(2x+1)), so:We add all the numbers together, and all the variables
6-4(2x+1)
determiningTheFunctionDomain -4(2x+1)+6
We multiply parentheses
-8x-4+6
We add all the numbers together, and all the variables
-8x+2
Back to the equation:
-(-8x+2)
10x-(-8x+2)-7=0
We get rid of parentheses
10x+8x-2-7=0
We add all the numbers together, and all the variables
18x-9=0
We move all terms containing x to the left, all other terms to the right
18x=9
x=9/18
x=1/2
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