5+2(c-5)=7(c-2)

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Solution for 5+2(c-5)=7(c-2) equation:


Simplifying
5 + 2(c + -5) = 7(c + -2)

Reorder the terms:
5 + 2(-5 + c) = 7(c + -2)
5 + (-5 * 2 + c * 2) = 7(c + -2)
5 + (-10 + 2c) = 7(c + -2)

Combine like terms: 5 + -10 = -5
-5 + 2c = 7(c + -2)

Reorder the terms:
-5 + 2c = 7(-2 + c)
-5 + 2c = (-2 * 7 + c * 7)
-5 + 2c = (-14 + 7c)

Solving
-5 + 2c = -14 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
-5 + 2c + -7c = -14 + 7c + -7c

Combine like terms: 2c + -7c = -5c
-5 + -5c = -14 + 7c + -7c

Combine like terms: 7c + -7c = 0
-5 + -5c = -14 + 0
-5 + -5c = -14

Add '5' to each side of the equation.
-5 + 5 + -5c = -14 + 5

Combine like terms: -5 + 5 = 0
0 + -5c = -14 + 5
-5c = -14 + 5

Combine like terms: -14 + 5 = -9
-5c = -9

Divide each side by '-5'.
c = 1.8

Simplifying
c = 1.8

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