5+2(x+4)=17-4(x+7)

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Solution for 5+2(x+4)=17-4(x+7) equation: 



5+2(x+4)=17-4(x+7)

We move all terms to the left:

5+2(x+4)-(17-4(x+7))=0

We multiply parentheses

2x-(17-4(x+7))+8+5=0



We calculate terms in parentheses: -(17-4(x+7)), so:

17-4(x+7)

determiningTheFunctionDomain
-4(x+7)+17

We multiply parentheses

-4x-28+17

We add all the numbers together, and all the variables

-4x-11

Back to the equation:

-(-4x-11)



We add all the numbers together, and all the variables

2x-(-4x-11)+13=0

We get rid of parentheses

2x+4x+11+13=0

We add all the numbers together, and all the variables

6x+24=0

We move all terms containing x to the left, all other terms to the right

6x=-24

x=-24/6

x=-4

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