5+2/7(x+4)+10=2(5-3,5)

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Solution for 5+2/7(x+4)+10=2(5-3,5) equation: 



5+2/7(x+4)+10=2(5-3.5)

We move all terms to the left:

5+2/7(x+4)+10-(2(5-3.5))=0



Domain of the equation: 7(x+4)!=0

x∈R



We add all the numbers together, and all the variables

2/7(x+4)+5+10-(2(1.5))=0

We add all the numbers together, and all the variables

2/7(x+4)+12=0

We multiply all the terms by the denominator


12*7(x+4)+2=0

Wy multiply elements

84x(x+2=0

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