If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5+2x^2=2x+6
We move all terms to the left:
5+2x^2-(2x+6)=0
We get rid of parentheses
2x^2-2x-6+5=0
We add all the numbers together, and all the variables
2x^2-2x-1=0
a = 2; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·2·(-1)
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{3}}{2*2}=\frac{2-2\sqrt{3}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{3}}{2*2}=\frac{2+2\sqrt{3}}{4} $
| 1/8(8x+15)=21 | | 10-2/3(9=12b) | | 9(5-3u)=5(u+7) | | 3(2x−1)−2(x−3)=5−(x−5) | | 2(4x-3)-3(1-2x)=12 | | -7x-6=9+3x | | -15x+24=34 | | 3*4+x+9x=108 | | 6q-28+7q=3+4q+5 | | 20x-40=15x+15 | | 5x-25=-2x+8 | | 2/3f-20=8 | | X²+2x*3+9=X²+2x*5+25 | | (x+3)²=(x+5)² | | (7x-74)=(5x-30) | | 12.25x13=x | | 64x^2+225x^2=(10-23x)^2 | | 2x(x+9)+60=180 | | -2d+6=-14 | | Y=20•x—5 | | -5/6-4/3x=8/9 | | (3x+16)=(4x+14) | | 6(x−2)=24 | | 2(2x-5)=3(5-2x) | | x2-4=13 | | 9x-21-3x=6x-9 | | (3x+24)=(x+58) | | 3x+24)=(x+58) | | 2+5k=–8+7k | | 8y^2-8y-169=0 | | T=5.5t+200 | | X2x3x=94 |