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5+2x=6(x+1)-5(x-2)
We move all terms to the left:
5+2x-(6(x+1)-5(x-2))=0
We calculate terms in parentheses: -(6(x+1)-5(x-2)), so:We get rid of parentheses
6(x+1)-5(x-2)
We multiply parentheses
6x-5x+6+10
We add all the numbers together, and all the variables
x+16
Back to the equation:
-(x+16)
2x-x-16+5=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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