5+2y+(5)(y-3)=(6)(y+1)

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Solution for 5+2y+(5)(y-3)=(6)(y+1) equation:


Simplifying
5 + 2y + (5)(y + -3) = (6)(y + 1)

Reorder the terms:
5 + 2y + 5(-3 + y) = (6)(y + 1)
5 + 2y + (-3 * 5 + y * 5) = (6)(y + 1)
5 + 2y + (-15 + 5y) = (6)(y + 1)

Reorder the terms:
5 + -15 + 2y + 5y = (6)(y + 1)

Combine like terms: 5 + -15 = -10
-10 + 2y + 5y = (6)(y + 1)

Combine like terms: 2y + 5y = 7y
-10 + 7y = (6)(y + 1)

Reorder the terms:
-10 + 7y = 6(1 + y)
-10 + 7y = (1 * 6 + y * 6)
-10 + 7y = (6 + 6y)

Solving
-10 + 7y = 6 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-10 + 7y + -6y = 6 + 6y + -6y

Combine like terms: 7y + -6y = 1y
-10 + 1y = 6 + 6y + -6y

Combine like terms: 6y + -6y = 0
-10 + 1y = 6 + 0
-10 + 1y = 6

Add '10' to each side of the equation.
-10 + 10 + 1y = 6 + 10

Combine like terms: -10 + 10 = 0
0 + 1y = 6 + 10
1y = 6 + 10

Combine like terms: 6 + 10 = 16
1y = 16

Divide each side by '1'.
y = 16

Simplifying
y = 16

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