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5+3(1x-4)=-2(1x+1)
We move all terms to the left:
5+3(1x-4)-(-2(1x+1))=0
We add all the numbers together, and all the variables
3(x-4)-(-2(x+1))+5=0
We multiply parentheses
3x-(-2(x+1))-12+5=0
We calculate terms in parentheses: -(-2(x+1)), so:We add all the numbers together, and all the variables
-2(x+1)
We multiply parentheses
-2x-2
Back to the equation:
-(-2x-2)
3x-(-2x-2)-7=0
We get rid of parentheses
3x+2x+2-7=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1
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