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5+3(2x+1)=-5+(3x+3)
We move all terms to the left:
5+3(2x+1)-(-5+(3x+3))=0
We multiply parentheses
6x-(-5+(3x+3))+3+5=0
We calculate terms in parentheses: -(-5+(3x+3)), so:We add all the numbers together, and all the variables
-5+(3x+3)
determiningTheFunctionDomain (3x+3)-5
We get rid of parentheses
3x+3-5
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
6x-(3x-2)+8=0
We get rid of parentheses
6x-3x+2+8=0
We add all the numbers together, and all the variables
3x+10=0
We move all terms containing x to the left, all other terms to the right
3x=-10
x=-10/3
x=-3+1/3
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