5+3(3u-5)=-6(3u-1)+9u

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Solution for 5+3(3u-5)=-6(3u-1)+9u equation: 



5+3(3u-5)=-6(3u-1)+9u

We move all terms to the left:

5+3(3u-5)-(-6(3u-1)+9u)=0

We multiply parentheses

9u-(-6(3u-1)+9u)-15+5=0



We calculate terms in parentheses: -(-6(3u-1)+9u), so:

-6(3u-1)+9u

We add all the numbers together, and all the variables

9u-6(3u-1)

We multiply parentheses

9u-18u+6

We add all the numbers together, and all the variables

-9u+6

Back to the equation:

-(-9u+6)



We add all the numbers together, and all the variables

9u-(-9u+6)-10=0

We get rid of parentheses

9u+9u-6-10=0

We add all the numbers together, and all the variables

18u-16=0

We move all terms containing u to the left, all other terms to the right

18u=16

u=16/18

u=8/9

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