5+3(Q-4)=2(Q-1)

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Solution for 5+3(Q-4)=2(Q-1) equation:


Simplifying
5 + 3(Q + -4) = 2(Q + -1)

Reorder the terms:
5 + 3(-4 + Q) = 2(Q + -1)
5 + (-4 * 3 + Q * 3) = 2(Q + -1)
5 + (-12 + 3Q) = 2(Q + -1)

Combine like terms: 5 + -12 = -7
-7 + 3Q = 2(Q + -1)

Reorder the terms:
-7 + 3Q = 2(-1 + Q)
-7 + 3Q = (-1 * 2 + Q * 2)
-7 + 3Q = (-2 + 2Q)

Solving
-7 + 3Q = -2 + 2Q

Solving for variable 'Q'.

Move all terms containing Q to the left, all other terms to the right.

Add '-2Q' to each side of the equation.
-7 + 3Q + -2Q = -2 + 2Q + -2Q

Combine like terms: 3Q + -2Q = 1Q
-7 + 1Q = -2 + 2Q + -2Q

Combine like terms: 2Q + -2Q = 0
-7 + 1Q = -2 + 0
-7 + 1Q = -2

Add '7' to each side of the equation.
-7 + 7 + 1Q = -2 + 7

Combine like terms: -7 + 7 = 0
0 + 1Q = -2 + 7
1Q = -2 + 7

Combine like terms: -2 + 7 = 5
1Q = 5

Divide each side by '1'.
Q = 5

Simplifying
Q = 5

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