5+3(d-4)=2(d+)

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Solution for 5+3(d-4)=2(d+) equation: 



5+3(d-4)=2(d+)

We move all terms to the left:

5+3(d-4)-(2(d+))=0

We add all the numbers together, and all the variables

3(d-4)-(2(+d))+5=0

We multiply parentheses

3d-(2(+d))-12+5=0



We calculate terms in parentheses: -(2(+d)), so:

2(+d)

We multiply parentheses

2d

Back to the equation:

-(2d)



We add all the numbers together, and all the variables

d-7=0

We move all terms containing d to the left, all other terms to the right

d=7

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