5+3(d-4)=2(d+1)

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Solution for 5+3(d-4)=2(d+1) equation:


Simplifying
5 + 3(d + -4) = 2(d + 1)

Reorder the terms:
5 + 3(-4 + d) = 2(d + 1)
5 + (-4 * 3 + d * 3) = 2(d + 1)
5 + (-12 + 3d) = 2(d + 1)

Combine like terms: 5 + -12 = -7
-7 + 3d = 2(d + 1)

Reorder the terms:
-7 + 3d = 2(1 + d)
-7 + 3d = (1 * 2 + d * 2)
-7 + 3d = (2 + 2d)

Solving
-7 + 3d = 2 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-7 + 3d + -2d = 2 + 2d + -2d

Combine like terms: 3d + -2d = 1d
-7 + 1d = 2 + 2d + -2d

Combine like terms: 2d + -2d = 0
-7 + 1d = 2 + 0
-7 + 1d = 2

Add '7' to each side of the equation.
-7 + 7 + 1d = 2 + 7

Combine like terms: -7 + 7 = 0
0 + 1d = 2 + 7
1d = 2 + 7

Combine like terms: 2 + 7 = 9
1d = 9

Divide each side by '1'.
d = 9

Simplifying
d = 9

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