5+3(q-4)=-1+2(q+-3)

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Solution for 5+3(q-4)=-1+2(q+-3) equation: 



5+3(q-4)=-1+2(q+-3)

We move all terms to the left:

5+3(q-4)-(-1+2(q+-3))=0

We add all the numbers together, and all the variables

3(q-4)-(-1+2(q-3))+5=0

We multiply parentheses

3q-(-1+2(q-3))-12+5=0



We calculate terms in parentheses: -(-1+2(q-3)), so:

-1+2(q-3)

determiningTheFunctionDomain
2(q-3)-1

We multiply parentheses

2q-6-1

We add all the numbers together, and all the variables

2q-7

Back to the equation:

-(2q-7)



We add all the numbers together, and all the variables

3q-(2q-7)-7=0

We get rid of parentheses

3q-2q+7-7=0

We add all the numbers together, and all the variables

q=0

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