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5+3(q-4)=2(q+1)=
We move all terms to the left:
5+3(q-4)-(2(q+1))=0
We multiply parentheses
3q-(2(q+1))-12+5=0
We calculate terms in parentheses: -(2(q+1)), so:We add all the numbers together, and all the variables
2(q+1)
We multiply parentheses
2q+2
Back to the equation:
-(2q+2)
3q-(2q+2)-7=0
We get rid of parentheses
3q-2q-2-7=0
We add all the numbers together, and all the variables
q-9=0
We move all terms containing q to the left, all other terms to the right
q=9
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