5+3(r-4)=2(r+1)

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Solution for 5+3(r-4)=2(r+1) equation:


Simplifying
5 + 3(r + -4) = 2(r + 1)

Reorder the terms:
5 + 3(-4 + r) = 2(r + 1)
5 + (-4 * 3 + r * 3) = 2(r + 1)
5 + (-12 + 3r) = 2(r + 1)

Combine like terms: 5 + -12 = -7
-7 + 3r = 2(r + 1)

Reorder the terms:
-7 + 3r = 2(1 + r)
-7 + 3r = (1 * 2 + r * 2)
-7 + 3r = (2 + 2r)

Solving
-7 + 3r = 2 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
-7 + 3r + -2r = 2 + 2r + -2r

Combine like terms: 3r + -2r = 1r
-7 + 1r = 2 + 2r + -2r

Combine like terms: 2r + -2r = 0
-7 + 1r = 2 + 0
-7 + 1r = 2

Add '7' to each side of the equation.
-7 + 7 + 1r = 2 + 7

Combine like terms: -7 + 7 = 0
0 + 1r = 2 + 7
1r = 2 + 7

Combine like terms: 2 + 7 = 9
1r = 9

Divide each side by '1'.
r = 9

Simplifying
r = 9

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