5+3(t-4)=2(t+1)

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Solution for 5+3(t-4)=2(t+1) equation:


Simplifying
5 + 3(t + -4) = 2(t + 1)

Reorder the terms:
5 + 3(-4 + t) = 2(t + 1)
5 + (-4 * 3 + t * 3) = 2(t + 1)
5 + (-12 + 3t) = 2(t + 1)

Combine like terms: 5 + -12 = -7
-7 + 3t = 2(t + 1)

Reorder the terms:
-7 + 3t = 2(1 + t)
-7 + 3t = (1 * 2 + t * 2)
-7 + 3t = (2 + 2t)

Solving
-7 + 3t = 2 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-7 + 3t + -2t = 2 + 2t + -2t

Combine like terms: 3t + -2t = 1t
-7 + 1t = 2 + 2t + -2t

Combine like terms: 2t + -2t = 0
-7 + 1t = 2 + 0
-7 + 1t = 2

Add '7' to each side of the equation.
-7 + 7 + 1t = 2 + 7

Combine like terms: -7 + 7 = 0
0 + 1t = 2 + 7
1t = 2 + 7

Combine like terms: 2 + 7 = 9
1t = 9

Divide each side by '1'.
t = 9

Simplifying
t = 9

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