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5+3(x-1)=3x-2(x-3)
We move all terms to the left:
5+3(x-1)-(3x-2(x-3))=0
We multiply parentheses
3x-(3x-2(x-3))-3+5=0
We calculate terms in parentheses: -(3x-2(x-3)), so:We add all the numbers together, and all the variables
3x-2(x-3)
We multiply parentheses
3x-2x+6
We add all the numbers together, and all the variables
x+6
Back to the equation:
-(x+6)
3x-(x+6)+2=0
We get rid of parentheses
3x-x-6+2=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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