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5+3(x-3)=11-2(x-5)
We move all terms to the left:
5+3(x-3)-(11-2(x-5))=0
We multiply parentheses
3x-(11-2(x-5))-9+5=0
We calculate terms in parentheses: -(11-2(x-5)), so:We add all the numbers together, and all the variables
11-2(x-5)
determiningTheFunctionDomain -2(x-5)+11
We multiply parentheses
-2x+10+11
We add all the numbers together, and all the variables
-2x+21
Back to the equation:
-(-2x+21)
3x-(-2x+21)-4=0
We get rid of parentheses
3x+2x-21-4=0
We add all the numbers together, and all the variables
5x-25=0
We move all terms containing x to the left, all other terms to the right
5x=25
x=25/5
x=5
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