5+3(x-4)=7-2(3x-1)

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Solution for 5+3(x-4)=7-2(3x-1) equation: 



5+3(x-4)=7-2(3x-1)

We move all terms to the left:

5+3(x-4)-(7-2(3x-1))=0

We multiply parentheses

3x-(7-2(3x-1))-12+5=0



We calculate terms in parentheses: -(7-2(3x-1)), so:

7-2(3x-1)

determiningTheFunctionDomain
-2(3x-1)+7

We multiply parentheses

-6x+2+7

We add all the numbers together, and all the variables

-6x+9

Back to the equation:

-(-6x+9)



We add all the numbers together, and all the variables

3x-(-6x+9)-7=0

We get rid of parentheses

3x+6x-9-7=0

We add all the numbers together, and all the variables

9x-16=0

We move all terms containing x to the left, all other terms to the right

9x=16

x=16/9

x=1+7/9

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