5+3(y+-4)=5(y+2)+-1y

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Solution for 5+3(y+-4)=5(y+2)+-1y equation: 



5+3(y+-4)=5(y+2)+-1y

We move all terms to the left:

5+3(y+-4)-(5(y+2)+-1y)=0

We add all the numbers together, and all the variables

3(y-4)-(5(y+2)+-1y)+5=0

We use the square of the difference formula

3(y-4)-(5(y+2)-1y)+5=0

We multiply parentheses

3y-(5(y+2)-1y)-12+5=0



We calculate terms in parentheses: -(5(y+2)-1y), so:

5(y+2)-1y

We add all the numbers together, and all the variables

-1y+5(y+2)

We multiply parentheses

-1y+5y+10

We add all the numbers together, and all the variables

4y+10

Back to the equation:

-(4y+10)



We add all the numbers together, and all the variables

3y-(4y+10)-7=0

We get rid of parentheses

3y-4y-10-7=0

We add all the numbers together, and all the variables

-1y-17=0

We move all terms containing y to the left, all other terms to the right

-y=17

y=17/-1

y=-17

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